Question

What are the relative frequencies to the nearest hundredth of the columns of the two-way table?

Answer 1

Answer:

                                     A                               B

Group 1.                     0.33                           0.81

Group 2.                    0.67                           0.19

Step-by-step explanation:

To answer this question we must add the frequencies of A and B

This is:

Group 1: f(A) = 24

Group 2: f(A) = 48

Total (A) = 24 + 48 = 72

Then

Group 1: f(B) = 44

Group 2: f(B) = 10

Total (B) = 44 +10 = 54

Now we divide each value of f(A) between the total of (A) and each value of f(B) between the total of (B)

                      A               B

Group 1.   $\frac{24}{72} = 0.33$    $\frac{44}{54} =0.81$  

Group 2.    $\frac{48}{72}=0.67$     $\frac{10}{54}=0.19$