Respuesta :
C is the answer you have to divide 21 by 3 first which gives you 3. The x cubed cancels out because when dividing exponents you have to subtracting. The y squared minus y gives you just y. This explains the 3y
Answer:
C.[tex]2x^{2}y^{3}+3y[/tex]
Step-by-step explanation:
We have the expression:
[tex]\frac{14x^5y^4+21x^3y^2}{7x^3y}[/tex]
which can be separeded in two terms, like this:
[tex]\frac{14x^5y^4}{7x^3y} +\frac{21x^3y^2}{7x^3y}[/tex]
and now we can simplify each term, dividing the coefficients and using the exponent law [tex]\frac{x^m}{x^n} =x^{m-n}[/tex] (when we divide a variable we substract the exponts) and we get the following:
[tex]2x^{5-3}y^{4-1}+3x^{3-3}y^{2-1}[/tex]
simplifying the exponents:
[tex]2x^{2}y^{3}+3y[/tex]
which is option C.