Can someone please help???
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Answer:
Option A
Step-by-step explanation:
We assume that after the first player and second player choose a card they do not return the card to the deck and that the events are mutually exclusive (ie, you can not get a queen and jack by selecting a single card).
It can be seen in the figure that there are 52 cards in the deck. It can be seen that there are 4 queens and 4 jacks.
Thus:
If the first player selected a jack, then there are only 3 jacks left in the deck, and 51 cards in total.
If the second player selected a queen, then there are only 3 queens left in the deck and 50 cards in total.
Therefore, the probability Pj that the third player selects a Jack
is [tex]P_{j} = \frac{3}{50}[/tex]
Then, the probability Pq that the third player selects a queen
is [tex]P_{q} = \frac{3}{50}[/tex]
Finally the probability of selecting a jack or queen is:
P(j ∪ q) = [tex]P_{j} + P_{q}[/tex]
P(j ∪ q) = [tex]\frac{3}{50} + \frac{3}{50}[/tex]
P(j ∪ q) = [tex]\frac{3}{25}[/tex].
The correct answer is the first option.