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Could someone answer this and explain an easier way to do this?


A semicircle and a quarter circle are attached to the sides of a rectangle as shown.

What is the area of this figure?

Use 3.14 for pi.

Enter your answer in the box. Round only your final answer to the nearest whole number.

Could someone answer this and explain an easier way to do this A semicircle and a quarter circle are attached to the sides of a rectangle as shown What is the a class=

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Answer:

Area of the figure = 109 cm. square

Step-by-step explanation:

The radius of the semi circle is 12 ÷ 2 = 6 cm.

Area of the semi circle = [tex]\frac{1}{2}\pi(6^{2})=18\pi[/tex]

The radius of the quarter circle is 6 cm.

Area of the quarter circle = [tex]\frac{1}{4}\pi(6^{2}=9\pi[/tex]

The area of the rectangle = 12 × 2 = 24

The area of the figure = 18π + 9π + 24 = 108.78 ≅ 109 cm. square

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