Respuesta :

Answer:

[tex]\boxed{f(x)=3x^2-2x+5}[/tex]

Step-by-step explanation:

Since we know that the function of the table is a quadratic function, we can start writing this function as follows:

[tex]f(x)=ax^2+bx+c[/tex]

Given that we have three variables [tex]a, \ b \ and \ c[/tex], we can solve this problem by taking three points, say:

[tex](0,5), \ (1,6) \ and \ (-1,10)[/tex]

So these points must satisfy the equation of the function. Therefore:

[tex]For \ (0,5) \\ \\5=a(0)^2+b(0)+c \\ \\ 5=c \rightarrow \boxed{c=5} \\ \\ \\ For \ (1,6) \\ \\ Solving \\ \\ 6=a(1)^2+b(1)+5 \\ \\ \boxed{a+b=1} \\ \\For \ (-1,10) \\ \\Solving \\ \\10=a(-1)^2+b(-1)+5 \\ \\\boxed{a-b=5}[/tex]

So we have two equations to solve for a and b:

[tex](1) \ a+b=1 \ and \ (2) \ a-b=5 \\ \\ From \ 1: \\ \\ a=1-b \\ \\ From \ 2:\\ \\ a=5+b \\ \\ \\Matching: \\ \\ 1-b=5+b \ Solving: \\ \\ 1-5=b+b \\ \\ \boxed{b=-2} \\ \\ Finally: \\ \\ a=1-(-2) \therefore \boxed{a=3}[/tex]

So the quadratic function represented by the table is:

[tex]\boxed{f(x)=3x^2-2x+5}[/tex]

The quadratic function which is represented by the provided table of x and f(x) is 3x^2-2x+5 in the quadratic equation form.

What is a quadratic function?

A quadratic function is the function in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic function is,

[tex]f(x)=ax^2+bx+c[/tex]

Here,(a,b, c) is the real numbers and (x) is the variable.

The values given in the table are,

  • x       f(x)
  • -2        21
  • -1         10
  • 0          5
  • 1           6
  • 2         13

Let the point (0,5) of the given table. Put these points in the above equation,

[tex]5=a(0)^2+b(0)+c\\5=0+0+c\\c=5[/tex]

The value of c is 5. Put this value in the above equaiton, with point (1, 6).

[tex]6=a(1)^2+b(1)+5\\a+b=6-5\\a+b=1[/tex]                 .....1

Now, the equation for the point (-1,10) is,

[tex]10=a(-1)^2+b(-1)+5\\a(1)+(-1)b=10-5\\a-b=5\\a=5+b[/tex]

Put this value in the equation 1 as,

[tex]a+b=1\\(5+b)+b=1\\2b=1-5\\b=\dfrac{-4}{2}\\b=-2[/tex]

The value of b is -2. Thus the value of a is,

[tex]a+(-2)=1\\a=1+2\\a=3[/tex]

Put the value of a,b and c in the quadratic function,

[tex]f(x)=3x^2-2x+5[/tex]

Thus, the quadratic function which is represented by the provided table of x and f(x) is 3x^2-2x+5 in the quadratic equation form.

Learn more about the quadratic function here;

https://brainly.com/question/14098045

ACCESS MORE