Respuesta :
Answer:
[tex]n-(9\frac{1}{10})[/tex]
Step-by-step explanation:
Let
n------> the total kg of sugar in stock
x-----> the kg of sugar left in stock
we know that
[tex]x=n-(5\frac{3}{5} +3\frac{1}{2})[/tex]
Convert mixed number to an improper fractions
so
[tex]5\frac{3}{5}=\frac{5*5+3}{5}=\frac{28}{5}[/tex]
[tex]3\frac{1}{2}=\frac{3*2+1}{2}=\frac{7}{2}[/tex]
substitute
[tex]x=n-(\frac{28}{5} +\frac{7}{2})[/tex]
[tex]x=n-(\frac{28*2+7*5}{10})[/tex]
[tex]x=n-(\frac{91}{10})[/tex]
convert to mixed number
[tex]x=n-(9\frac{1}{10})[/tex]