Question

Which equation has the solutions

2x2 + 6x + 9 = 0
x2 + 3x + 12 = 0
x2 + 3x + 3 = 0
2x2 + 6x + 3 = 0

Answer 1

Answer:

x² + 3x + 3 = 0  has this solution

Step-by-step explanation:

x² + 3x + 3 = 0

Using quadratic formula to solve it:

$x = \frac{-b +- \sqrt{b^2-4ac} }{2a}$

from above equation

a = 1 ,  b = 3, c = 3

$x = \frac{-3 +- \sqrt{3^2-4(1)(3)} }{2(1)}$

$x = \frac{-3 +- \sqrt{9-12} }{2}$

$x = \frac{-3 +- \sqrt{3}i}{2}$

Answer 2

Answer:

Choice C is the correct solution

Step-by-step explanation:

Identify and separate the roots of the equation. The next step involves taking all values to one side of the equation so that the other side is just zero. Finally, we multiply the two roots and simplify the expression hen equate to zero.