Identify a possible first step using the elimination method to solve the system and then find the solution to the system. 3x - 5y = -2 & 2x + y = 3
A) Multiply first equation by -3 and second equation by 2, solution (1, 1).
B) Multiply first equation by -2 and second equation by 3, solution (1, 1).
C) Multiply first equation by -3 and second equation by 2, solution (1, -1).
D) Multiply first equation by -2 and second equation by 3, solution (1, -1).

Respuesta :

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

3x - 5y = - 2 → (1)

2x + y = 3 → (2)

Multiply (2) by 5 will eliminate y when added to (1), that is

10x + 5y = 15 → (3)

Add (1) and (3) term by term

(3x + 10x) + (- 5y + 5y) = (- 2 + 15)

13x = 13 ( divide both sides by 13 )

x = 1

Substitute x = 1 into (2) for corresponding value of y

2 + y = 3 ⇒ y = 3 - 2 = 1

Solution is (1, 1)

The correct possible option is B) Multiply first equation by -2 and second equation by 3, solution (1, 1).

Given, set of equations are [tex]3 x - 5 y = -2[/tex] .....(1)

And [tex]2 x + y = 3[/tex]....(2)

We have to solve these equations by elimination method, so we multiply equation 1 by -2 and equation 2 by 3, we get

[tex]-6 x + 10 y = 4[/tex]......(3)

[tex]6x+3y=9[/tex]....(4)

On adding equation 3 and equation 4, we get

[tex]13y=13[/tex]

[tex]y=1[/tex]

Now put the value of [tex]y=1[/tex] in equation 3 we get,

[tex]-6x+10\times1=4[/tex]

[tex]-6x+10=4[/tex]

[tex]-6x=4-10[/tex]

[tex]-6x=-6[/tex]

[tex]x=1[/tex].

Hence we have to first multiply equation 1 by -2 and second equation by 3 so the solution of the system of equation is (1,1).

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