If 14.50 mL of 0.25 M sodium hydroxide reacts completely with 25.0 mL of hydrochloric acid, what is the concentration of the hydrochloric acid?

Respuesta :

Answer: The concentration of the hydrochloric acid is 0.145 M.

Explanation: [tex]HCl+NaOH\rightarrow NaOH+H_2O[/tex]

According to given balanced equation, 1mole of HCL require 1 mole of NaOH.

Using Molarity equation:

[tex]M_1V_1=M_2V_2[/tex]

[tex]M_1[/tex] = Molarity of base= 0.25 M

[tex]V_1[/tex] = volume of base= 14.50 ml

[tex]M_2[/tex] = Molarity of acid = ? M

[tex]V_2[/tex] = volume of acid = 25 ml

[tex]0.25\times 14.50=M_2\times 25[/tex]

[tex]M_2=0.145M[/tex]