Question

Could use someone’s help please

Answer 1

Answer:

A

Step-by-step explanation:

Since i = 1 to 3, it is probably quicker to evaluate each sum, that is

4 × $\frac{1}{2} ^{0}$ + 4 × $\frac{1}{2} ^{1}$ + 4 × ($\frac{1}{2}$))²

= (4 × 1) + (4 × $\frac{1}{2}$) + (4 × $\frac{1}{4}$)

= 4 + 2 + 1

= 7 → A