Answer:
Length of the tunnel is 51.7 meters
Step-by-step explanation:
We are given that,
The surveyor is located 54 meters from one entrance at an angle of 56°.
The surveyor is located 31 meters from one entrance at an angle of 13°.
Let the length of the tunnel = x meters
So, using the law of cosines, we get,
[tex]x^2=54^2+31^2-2\times 54\times 31\times \cos 69[/tex]
i.e. [tex]x^2=2916+961-3348\times 0.3584[/tex]
i.e. [tex]x^2=3877-1199.9[/tex]
i.e. [tex]x^2=2677.1[/tex]
i.e. x = 51.7 meters
Hence, the length of the tunnel is 51.7 meters