Answer:
Total amount of wrapping required = 252 inch²
Step-by-step explanation:
Dimensions of the 1st box are given by,
Length = 1 inch, Width = 7 inch and Height = 3 inch
As, Surface area of a rectangular box = [tex]2(Length\times Width+Length\times Height+Height\times Width)[/tex]
So, Surface area of the 1st box = [tex]2(1\times 7+1\times 3+3\times 7)[/tex]
i.e. Surface area of the 1st box = [tex]2(7+3+21)[/tex]
i.e. Surface area of the 1st box = 2 × 31 = 62 inch²
Further, we have,
Dimensions of the 2nd box are given by,
Length = 2 inch, Width = 7 inch and Height = 9 inch
So, Surface area of the 2nd box = [tex]2(2\times 7+2\times 9+9\times 7)[/tex]
i.e. Surface area of the 2nd box = [tex]2(14+18+63)[/tex]
i.e. Surface area of the 2nd box = 2 × 95 = 190 inch²
Thus, the total amount of wrapping required = 62 + 190 = 252 inch².