Respuesta :
Answer:(−∞,-13)
Step-by-step explanation:
solve for x the convert to interval notation
x<-13 → (−∞,-13)
Since it's a < and not a ≤ you use a parentheses instead of a bracket
Answer:
[tex]\large\boxed{x<-13\to x\in(-\infty,\ -13)}[/tex]
Step-by-step explanation:
[tex]x+13<0\qquad\text{substract 13 from both sides}\\\\x+13-13<0-13\\\\x<-13[/tex]