Respuesta :
In Honolulu, 57 degrees is a little less than three standard deviations below the average temperature. In Anchorage, 57 degrees is 3.6 standard deviations above the average. 3.6 standard deviations is more than 3, meaning it would be more unusual to reach 57 degrees in Anchorage than in Honolulu.
Answer:
It would be more unusual to have a day in January with a high of 57ºF in Anchorage, Alaska.
Step-by-step explanation:
The average high temperature in Anchorage, Alaska, in January is 21°F with a standard deviation of 10°. This means that, in certain uncommon conditions, it can even reach 31ºF. So, a temperature of 57ºF would be as far as 26º from the limit of the standard deviation.
In the caso of Honolulu, the average high temperature in the same month is of 80ºF, but it can be of 72ºF in certain climatic situations. So, a temperature of 57ºF would be 15º below the limit of the standard deviation, much near than the 27º from Anchorage and, as a consequence, more likely to reach this temperature in a very strange climatic situation.
With this analysis, we can affirm that it would be more unusual to have a day in January with a high of 57ºF in Anchorage rather than Honolulu.