Solar flux that incident on it is given as
S = 160 W/m/m
Now we know that the area of solar panels is given as
A = 10 m^2
So total solar power received by solar panels is given as
[tex]Power Received = (Solar flux) \times (Area)[/tex]
[tex]P = S\times A[/tex]
now here we have
[tex]P = 160 \times 10 [/tex]
[tex]P = 1600 W[/tex]
now we know that efficiency of the solar panels is 20%
so total output power will be
[tex]efficiency = \frac{P_{out}}{P_{in}}[/tex]
[tex]0.20 = \frac{P_{out}}{1600}[/tex]
[tex]P_{out} = 320 W[/tex]