Question

How do I solve (x+1)(x+2)=(x+3)(x-1)?

Answer 1

First you expand the brackets:
X^2+3x+2=x^2+2x-3
Take away x^2 from both sides
3x+2=2x-3
Then you get rid of the 2x from one side
x+2=-3
Take 2
x=-5
Therefore -5 is your answer to x, hope this helps

Answer 2

Answer: x = -5

Step-by-step explanation:

(x + 1)(x + 2) = (x + 3)(x - 1)

x² + 3x + 2 = x² + 2x - 3         Foiled both sides

       3x + 2 =        2x - 3        Subtracted x² from both sides

         x + 2 =             - 3        Subtracted 2x from both sides

         x       =              - 5        Subtracted 2 from both sides

Check:

(-5 + 1)(-5 + 2) = (-5 + 3)(-5 - 1)

  (-4)      (-3)    =    (-2)     (-6)

         12          =          12         $\checkmark$