Question

A balanced dime is tossed three times. The possible outcomes are represented in the table.

HHH
HTH
THH
TTH
HHT
HTT
THT
TTT

(a) Find the probability that the last two tosses come up the same.

Answer 1

the last two ones be the same, the outcomes would be TTT,HTT,THH,HHH

so the probability is 4/8 = 1/2.

Answer 2

The probability that the last two tosses come up the same is $\frac{1}{2}$.

What is probability?

The probability indicates the chance of happening of a particular event or incident.

The total number of events is 8.

The favorable events is the number of cases where the last two tosses come up the same $=({HHH, THH, HTT, TTT) = 4$.

Therefore, the required probability is

$= \frac{4}{8}\\ = \frac{1}{2}$

Learn more about probability here: https://brainly.com/question/10837034

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