Question

A jet engine develops 1.0 x 10 N of thrust to move an airplane forward
at a speed of 9.0 x 10 km/h. What
is the power output of the engine?

Answer 1

So P = 1.0x10^5N*(900km/h*1000m/km*1h/3600s) = 2.5x10&6W = 25 MW ans c

Answer 2

Answer:

Power, $P=25\times 10^6\ W$

Explanation:

Given that :

Force applied to the engine, $F=1\times 10^5\ N$

Speed of the engine, $v=9\times 10^2\ km/h=250\ m/s$

To find :

The power output of the engine

Solve :

Power output of the engine is given by :

$P=\dfrac{W}{t}$

W is the work done

t is the time taken

Also, $W=F\times d$ and $v=\dfrac{d}{t}$

$P=\dfrac{F\times d}{t}$

$P=F\times v$

$P=1\times 10^5\ N\times 250\ m/s$

$P=25\times 10^6\ W$

So, the power output of the engine is $25\times 10^6\ W$.