Consider the first four terms of the sequence below.
What is the 8th term of this sequence?
![Consider the first four terms of the sequence below What is the 8th term of this sequence class=](https://us-static.z-dn.net/files/d41/42641e4c6271e1b6deb17a64c3828b5f.png)
Answer:
a₈ = - 1 / 128
Step-by-step explanation:
Given:
First four terms of the sequence
a₁= 1, a₂= - 1/2, a₃= 1/4 and a₄= -1/8
First we recognize that this is a geometric series (sequence) and we must calculate quotient q.
q = a₂/a₁ = a₃/a₂ = (-1/2)/1 = (1/4)/(-1/2) = - 1/2
q = - 1/2
Formula for calculating n-th term is:
aₙ = a₁ · qⁿ⁻¹
According to this:
a₈ = 1 (-1/2)⁷ = - 1/ 128
God with you!!!