Respuesta :
Answer
the ratio of kinetic energies of oxygen molecule and hydrogen molecule if oxygen is 16 times heavier than hydrogen is 1
Explanation
The average kinetic energy of a gas molecule at temperature T is given by following formula
[tex]E =\frac{3kT}{2}[/tex]...............(1)
Here k is Boltzmann's constant ([tex]k=1.38\times 10^{-23} JK^{-1}[/tex]).
From above equation it is clear that average kinetic energy of a gas molecule only depends on temperature.
Therefore kinetic energy of oxygen molecule [tex]E_{1}=\frac{3kT}{2}[/tex]....2
and kinetic energy of hydrogen molecule [tex]E_{2}=\frac{3kT}{2}[/tex]....3
the ratio of kinetic energies of oxygen molecule and hydrogen molecule if oxygen is 16 times heavier than hydrogen is given as
[tex]\frac{E_{1}}{E_{2}} =\frac{\frac{3kT}{2}}{\frac{3kT}{2}}[/tex]
[tex]\frac{E_{1}}{E_{2}}=1[/tex]
Therefore, the ratio of kinetic energies of oxygen molecule and hydrogen molecule if oxygen is 16 times heavier than hydrogen is 1
The ratio of kinetic energies of the oxygen molecule and hydrogen molecule if oxygen is 16 times heavier than hydrogen will be 1.
What is average kinetic energy?
The average kinetic energy (KE) is defined as the one-half of the mass of each gas molecule times multiplied by the square of RMS velocity.
The average kinetic energy is found as;
[tex]\rm E = \frac{3kT}{2} \\\\[/tex]
KE is the kinetic energy
m is the mass of each molecule[tex](V)_{rms}[/tex]
[tex](V)_{rms}[/tex]v is the RMS velocity
The above relation shows that the kinetic energy is independent of the atomic weight of the molecule. Ao that the ratio of the kinetic energy is found as;
[tex]\rm \frac{E_1}{E_2} = 1[/tex]
Hence the ratio of kinetic energies of the oxygen molecule and hydrogen molecule if oxygen is 16 times heavier than hydrogen will be 1.
To learn more about the average kinetic energy refer to the link ;
brainly.com/question/24134093
