ANSWER
[tex]a) \frac{8}{5} m[/tex]
[tex]b) \frac{2}{5} m[/tex]
EXPLANATION
The length of Linda's orange ribbon is
[tex] = 2m[/tex]
a)
The length of the blue ribbon is
[tex] = \frac{4}{5} \times 2m[/tex]
[tex] = \frac{8}{5} m[/tex]
The length of the blue ribbon before it was cut is
[tex] = \frac{8}{5} m[/tex]
Or
[tex] = 1 \frac{3}{5} m[/tex]
b)
The piece of blue ribbon Linda cut off is
[tex] = 25\% \: of \: \frac{8}{5} [/tex]
[tex] = \frac{25}{100} \times \frac{8}{5} m[/tex]
Cancel the common factors to get,
[tex] = \frac{5}{100} \times \frac{8}{1} m[/tex]
[tex] = \frac{40}{100} m[/tex]
[tex] = \frac{2}{5}m[/tex]
The piece of the blue ribbon Linda cut off
is
[tex] \frac{2}{5} m[/tex]
long.