ANSWER
C) 5.1 units
EXPLANATION
The coordinates of A are (5,2).
If this point is translated 1 unit to the left and 5 units down to create point A'.
Then A' has coordinates
[tex]A(5,2)\rightarrow \: A'(5-1,2-5)[/tex]
[tex]A(5,2)\rightarrow \: A'(4, - 3)[/tex]
The distance between A and A' is calculated using the distance formula,
[tex] |AA'| = \sqrt{ {(5 - 4)}^{2} + {(2 - - 3}^{2} } [/tex]
[tex] |AA'| = \sqrt{ {(1)}^{2} + {(5)}^{2} } [/tex]
[tex] |AA'| = \sqrt{ 26} [/tex]
[tex] |AA'| = 5.099[/tex]
We round to the nearest tenth to obtain,
[tex] |AA'| =5.1 \: units[/tex]
The measurement that is closed to the distance is 5.1 units