Answer:
Option A. [tex]2x^{3}+7x^{2}+12x-8[/tex]
Step-by-step explanation:
we have
[tex](x^{2}+4x+8)(2x-1)[/tex]
Applying the distributive property
[tex](x^{2}+4x+8)(2x-1) =x^{2}(2x)-x^{2} +4x(2x)-4x+8(2x)-8\\ \\=2x^{3}-x^{2} +8x^{2}-4x+16x-8\\ \\= 2x^{3}+7x^{2}+12x-8[/tex]