Question

choose the quadratic equation that has a leading coefficient of 8 and solutions -10 and 7/8

Answer 1

Answer:

$f(x)=8x^2+73x-70$

Step-by-step explanation:

We are given

zeros as -10 and 7/8

now, we can set up function as

$f(x)=a(x-(-10))(x-\frac{7}{8})$

now, we are given that

leading coefficient is 8

so, a=8

now, we can plug it

$f(x)=8(x-(-10))(x-\frac{7}{8})$

now, we can simplify it

$f(x)=8\left(x^2+\frac{73x}{8}-\frac{35}{4}\right)$

so, we get

$f(x)=8x^2+73x-70$