Answer:
Option b is the correct choice.
Step-by-step explanation:
We are asked to find the which of our given expressions has 13y as a term.
Since we know that a term can be a signed number, a variable, or a constant multiplied by a variable or variables as 2a or 5b. In term 2a, 2 is coefficient and a is a variable.
We can see that in 13y, 13 is coefficient and y is variable.
Let us see our given choices one by one.
a. [tex]\frac{13y}{4}-2y[/tex]
Let can write our 1st term as:
[tex]\frac{13}{4}y-2y[/tex]
We can see that both of our terms have y variable, but our 1st term has a coefficient 13/4 and 2nd term has a coefficient of -2. As none of these terms have 13 as a coefficient, therefore, option a is not a correct choice.
b. [tex]8+13y-yz[/tex]
We can see that 8 is a constant, while 13y and -yz are terms. Since our expression has 13y as a term, therefore, option b is the correct choice.
c. [tex]4+13yz[/tex]
We can see that 4 is a constant and 13yz is a term as it has variables yz. Since our given term has two variables, therefore, option c is not a correct choice as well.
d. [tex]13+y[/tex]
We can see that 13 is a constant and y is term of our given expression. Since our expression don't have 13 as coefficient, therefore, option d is not a correct choice.