Respuesta :

Answer:

INT arcsin (x) dx  =  x arcsin(x)  + √(1 - x^2) + C .

Step-by-step explanation:

Use substitution and integration by parts:

Let t = arc sinx then  x = sin t and  dx = cos t dt

So INT arcsin x dx = INT t cost dt

Now integrate by parts:-

let u = t and dv = cos t dt

then:

du = 1 and v = sin t dt

The formula for integation by parts is

INT u dv = uv - INT  vdu so:

INT t cost dt =  t sin t - INT 1* sint dt

= t sint - (- cos t)  + C

= t sint + cos t + C.

Now substituting back for t, we have:

arcsin x * sin (arcsin x) + cos (arcsin x) + C.

Now sin (acrsin x)  = x  and cos (arcsin x) = √(1 - x^2) so we have

INT arcsin x dx =  x arcsin x  + √(1 - x^2) + C  (answer).

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