Respuesta :
Answer:
Thus, the two root of the given quadratic equation [tex]x^2+4=6x[/tex] is 5.24 and 0.76 .
Step-by-step explanation:
Consider, the given Quadratic equation, [tex]x^2+4=6x[/tex]
This can be written as , [tex]x^2-6x+4=0[/tex]
We have to solve using quadratic formula,
For a given quadratic equation [tex]ax^2+bx+c=0[/tex] we can find roots using,
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] ...........(1)
Where, [tex]\sqrt{b^2-4ac}[/tex] is the discriminant.
Here, a = 1 , b = -6 , c = 4
Substitute in (1) , we get,
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
[tex]\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}[/tex]
[tex]\Rightarrow x=\frac{6\pm\sqrt{20}}{2}[/tex]
[tex]\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}[/tex]
[tex]\Rightarrow x={3\pm \sqrt{5}}[/tex]
[tex]\Rightarrow x_1={3+\sqrt{5}}[/tex] and [tex]\Rightarrow x_2={3-\sqrt{5}}[/tex]
We know [tex]\sqrt{5}=2.23607[/tex](approx)
Substitute, we get,
[tex]\Rightarrow x_1={3+2.23607}[/tex](approx) and [tex]\Rightarrow x_2={3-2.23607}[/tex](approx)
[tex]\Rightarrow x_1={5.23607}[/tex](approx) and [tex]\Rightarrow x_2=0.76393}[/tex](approx)
Thus, the two root of the given quadratic equation [tex]x^2+4=6x[/tex] is 5.24 and 0.76 .
Answer:
The final answers are x = 5.24 OR x = 0.76
Step-by-step explanation:
Given the equation is x^2 +4 = 6x
Rewriting it in quadratic form as:- x^2 -6x 4 = 0.
a = 1, b = -6, c = 4.
Using Quadratic formula as follows:- x = ( -b ± √(b² -4ac) ) / (2a)
x = ( 6 ± √(36 -4*1*4) ) / (2*1)
x = ( 6 ± √(36 -16) ) / (2)
x = ( 6 ± √(20) ) / (2)
x = ( 6 ± 4.47 ) / (2)
x = (6+4.47) / (2) OR x = (6-4.47) / (2)
x = 10.47/2 OR x = 1.53/2
x = 5.235 OR x = 0.765
Hence, final answers are x = 5.24 OR x = 0.76