Question

what is the equation to a graph with the vertex -1,3 and zeros -4 and -2

Answer 1

Answer:

$f(x)=x^2+6x+8$

Step-by-step explanation:

We are given zeros as x=-4, x=-2

so, we can set up function as

$f(x)=a(x+4)(x+2)$

Vertex is at (-1,3)

It means that graph passes through point (-1,3)

so, we can plug x=-1 and f(x)=3

and then we can solve for 'a'

$3=a(-1+4)(-1+2)$

we get

$a=1$

now, we can plug it back

and we get

$f(x)=1(x+4)(x+2)$

now, we can simplify it

$f(x)=x^2+6x+8$