Respuesta :
Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
[tex]\text{Hypotenuse side}^2 = \text{Adjacent side}^2 + \text{opposite side}^2[/tex]
then;
[tex]\text{HK}^2 = 15^2+17^2 = 225 + 289 = 514[/tex]
or
[tex]HK = \sqrt{514} =22.671581[/tex] miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles

Answer:
The answer is 26.7
Step-by-step explanation:
I got it right from Khan Academy. First you get 22.67 miles but then you have to round it to the nearest tenth to get 22.7