Respuesta :

Answer:

As per the statement:

Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.

Let  H represents  Hawick , A represents Abbotsford and K represents Kelso

See the diagram as shown below:

Distance of AH = 15 miles

Distance of AK = 17 miles.

We have to find the distance HK:

Using Pythagoras theorem;

[tex]\text{Hypotenuse side}^2 = \text{Adjacent side}^2 + \text{opposite side}^2[/tex]

then;

[tex]\text{HK}^2 = 15^2+17^2 = 225 + 289 = 514[/tex]

or

[tex]HK = \sqrt{514} =22.671581[/tex] miles.

Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles

Ver imagen OrethaWilkison

Answer:

The answer is 26.7

Step-by-step explanation:

I got it right from Khan Academy. First you get 22.67 miles but then you have to round it to the nearest tenth to get 22.7

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