Ric made two investments: Investment \text{Q}Q has a value of \$500$500 at the end of the first year and increases by \$45$45 per year. Investment \text{R}R has a value of \$400$400 at the end of the first year and increases by 10\%10% per year. Eric checks the value of his investments once a year, at the end of the year. What is the first year in which Eric sees that investment \text{R}R's value exceeded investment \text{Q}Q's value?

Respuesta :

Answer: 9 year (approx)

Step-by-step explanation:

Since, In the Investment R,

The initial amount = $500

Which is increasing by $45 per year,

Thus, the total amount after x years in investment R = 500 + 45 x

In the investment Q,

The initial amount = $400

Which is increasing by 10% per year,

Thus, the total amount after x years in investment Q = [tex]400( 1 + \frac{10}{100})^x = 400(1+0.1)^x = 400(1.1)^x[/tex]

Since, the intersection point of the equations y =500+45x and y = 400(1.1)^x

are (-6.178, 221.992) and (8.069, 863.12)

But we can not take a negative number as a number of year,

Thus, the year in which both investment will equal is 8.069

After that the investment Q will be exceed the investment R,

The first year at which the investment Q will be exceed the investment R is approx 9th year.

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Answer:

10th year

Step-by-step explanation:

Ric made two investments.

Investment Q

Amount = $500 at end of the year

Increase $45 per year.

Value of investment after x year

[tex]A_{Q}=500+45(x-1)[/tex]

we take time (x-1) because investment was end of first year.

Investment R

Amount = $400 at end of the year

Increase 10% per year.

Value of investment after x year

[tex]A_{R}=400(1+.1)^{x-1}[/tex]

we take time (x-1) because investment was end of first year.

Eric checks the value of his investments once a year, at the end of the year.

Eric sees that investment R's value exceeded investment Q's value

Investment R > Investment Q

[tex]400(1+.1)^{x-1}>500+45(x-1)[/tex]

Using graphing calculator

[tex]x>9.06[/tex]

Hence, In 10th year Investment R could be greater than Investment Q

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