A fireman is standing 30 m directly west of a burning building. His ladder reaches 50m up the side of the building. What is the angle of elevation to the closest degree of his ladder?

Respuesta :

Answer:

As per the statement:

You can see the diagram as shown below.

Distance of fireman stands away from the building = 30 m

Length of the ladder = 50 m

Using Cosine ratio:

[tex]\cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse side}}[/tex] ....[1]

From the diagram:

Adjacent side = 30 m

Hypotenuse side = 50 m

Substitute these values in [1] to solve for angle of elevation([tex]\theta[/tex])

[tex]\cos \theta = \frac{30}{50} = 0.6[/tex]

or

[tex]\theta = \cos^{-1} (0.6)[/tex]

Simplify:

[tex]\theta = 53.13^{\circ}[/tex]

Therefore, the angle of elevation to the closest degree of the ladder is 51.13 degree

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