Please helpppp
The area of a rectangle is 5.612×10 to the 14th power centimeters square. The length of the rectangle is 9.2×10 to the 7 cm . Find the perimeter of the rectangle.

The area of a rectangle is A = L*W. This means [tex]A = 5.612*10^{14}[/tex] and [tex]L = 9.2*10^7[/tex] then the area of the rectangle in the formula would be:

[tex]5.612*10^14 = 9.2*10^7 (W)\\W = \frac{5.612*10^14}{9.2*10^7} \\W = 0.61 * 10 ^7 = 6.1*10^6[/tex]

To find the perimeter, add each of the sides. The length is [tex]9.2*10^7[/tex] and the width is [tex]6.1*10^6[/tex].

[tex]P = 9.2*10^7 + 9.2*10^7 + 6.1*10^6+6.1*10^6\\P = 18.4*10^7 + 12.2*10^6\\P = 184000000+12200000\\P = 1.962 * 10^8[/tex]

Please helpppp The area of a rectangle is 5.612×10 to the 14th power centimeters square. The length of the rectangle is 9.2×10 to the 7 cm . Find the perimeter of the rectangle.

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Please helpppp
The area of a rectangle is 5.612×10 to the 14th power centimeters square. The length of the rectangle is 9.2×10 to the 7 cm . Find the perimeter of the rectangle.