Answer:
6.6 moles.
Explanation:
Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O.
Now, using cross multiplication:
1.0 mole of Cu produces → 2.0 moles of NO₂, from the stichiometry,
∴ 3.3 moles of Cu produces → ??? moles of NO₂.
∴ the number of moles of NO₂ will form when 3.3 moles of Cu are reacted with excess HNO₃ is = (3.3 moles of Cu) (2.0 moles of NO₂) / (1.0 mole of Cu ) = 6.6 moles.