Answer:
Option B is correct.
direct variation; k = 5/2
Step-by-step explanation:
The Direct variation says:
[tex]y \propto x[/tex]
then the equation is of the form: [tex]y = kx[/tex] ......[1] where k is the constant of variation.
From the given table:
Consider x = -2 and y = -5
Substitute these in [1] to solve for k;
[tex]-5 = -2k[/tex]
or
5 = 2k
Divide both sides by 2 we get;
[tex]k = \frac{5}{2}[/tex]
⇒ the equation becomes: [tex]y = \frac{5}{2}x[/tex]
Check:
Take x = 4 and y = 10;
[tex]y = \frac{5}{2}x[/tex]
[tex]10 = \frac{5}{2} \times 4[/tex]
[tex]10 = 5 \times 2[/tex]
10 = 10 True
Therefore, the direct variation ; [tex]k = \frac{5}{2}[/tex] best describe the function represented by the table