Respuesta :

Answer:


Step-by-step explanation:

The given equation is a quadratic which can be solved by quadratic formula or also completing the square.

we can easily complete the square here so using this concept on the given equation we get

[tex]x^{2} -2x-62=0\\x^{2} -2x +1^{2} -1^2-62=0[/tex]

[tex](x-1)^{2} -63=0\\(x-1)^{2} =63[/tex]

Take square root on both sides of the equation which gives us

[tex]x-1 =\sqrt{63}[/tex]

solution

x=1± sqrt{63}

x=1±3sqrt7

So option B is correct .

Answer:

Choice B is correct answer.

Step-by-step explanation:

Given equation is :

x²-2x-62= 0

ax²+bx+c = 0 is general quadratic equation.

x = (-b±√b²-4ac) / 2a is quadratic formula to solve general quadratic equation.

Comparing given equation with general quadratic equation,we get

a = 1 , b = -2 and c = -62

Putting above values in quadratic formula: we get

x = (-(-2)±√(-2)²-4(1)(-62)) / 2(1)

x = ( 2±√4+248)  / 2

x = (2±√252) / 2

x = (2±√36×7) / 2

x = (2±6√7) / 2

x = 2(1±3√7) /2

x = 1±3√7 is solution of given equation.

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