Question

Solve for x....................

Answer 1

Answer:

Option D is correct.

Step-by-step explanation:

We have been given an equation:

$6x^2-2x+3=0$

On comparing the general quadratic equation:

$ax^2+bx+c$

a=6, b=-2 and c=3

Here, we will find discriminant

By using$D=b^2-4ac$

$b^2-4ac=(-2)^2-4(6)(3)$

$D=-68$

Since, discriminant is negative

Therefore, no real solutions

Therefore, option D is correct.

Answer 2

Answer:

Choice D is correct answer.

Step-by-step explanation:

Given equation is :

6x²-2x+3= 0

ax²+bx+c =0 is general quadratic equation.

x = (-b±√b²-4ac) / 2a is quadratic formula to find the solution of quadratic equation.

Comparing general equation with quadratic equation, we get

a = 6 ,b = -2 and c = 3

putting above values in quadratic formula, we get

x = (-(-2)±√(-2)²-4(6)(3)) / 2(6)

x = (2±√4-72) / 12

x = ( 2±√-68) / 12

Since, √-68 is complex number which is in the solution of given equation.

Hence, given equation has no real solution.