Which complex number has a distance of square root of 17 from the origin on the complex plane?

Answer:
OptionD
Step-by-step explanation:
4-i option d is the answer
REcall that when z =a+ib for a complex number distance from origin is
modulus z
|z|=[tex]\sqrt{a^2+b^2}[/tex]
Apply the above rule for each option
Option 1.
Distance =[tex]\sqrt{2^2+15^2}=\sqrt{229}[/tex] not our answer
Similarly for option b
Distance = \sqrt{17^2+1^2}=\sqrt{290} not our answer
Option c:
\sqrt{20^2+3^2}=\sqrt{409}not matching with given value
Option d
Distance=\sqrt{4^2+1^2}=\sqrt{17}=given answer
Hence option d is right