Question

At 35.0°C and 3.00 atm pressure, a gas has a volume of 1.40 L. What pressure does the gas have at 0.00°C and a volume of 0.950 L?

Which equation should you use?


P2= P1V1T2/T1V2


What is the pressure of the gas?


3.92 atm

These are the answers

Answer 1

The answer to your question is

A. P2=P1V1T2/T1V2

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I hope this helps

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Answer 2

Answer:

The final pressure is 3.92 atm

Explanation:

Given:

Initial conditions                                    

Temperature, T1 = 35.0 C

Pressure, P1 = 3.00 atm

Volume, V1 = 1.40 L

Final conditions

Temperature, T2 = 0.0 C

Volume, V2 = 0.950 L

To determine:

Final pressure, P2

Explanation:

Based on the ideal gas equation

$PV = nRT$

where P = pressure, V = volume ; n = moles of gas

R = gas constant, T = temperature

At constant n, the above equation becomes:

$\frac{PV}{T} = constant$

Therefore,

$\frac{P1V1}{T1} = \frac{P2V2}{T2}\\\\P2 = \frac{P1V1}{T1}*\frac{T2}{V2} = \frac{3.00atm*1.40L}{(35+273)K}*\frac{(0+273)K}{0.950L}=3.92\ atm$