The first two. In fact, you have
[tex] \sqrt{20} = \sqrt{4\cdot 5} = \sqrt{4}\cdot \sqrt{5} = 2\sqrt{5} [/tex]
and [tex] \sqrt{5} [/tex] is irrational.
Similarly, [tex] \pi [/tex] is irrational, and the same goes for [tex] 4\pi [/tex].
Instead, the square root and the second power simplify in the third option:
[tex] \left(\sqrt{13}\right)^2 = 13 [/tex]
and similarly,
[tex] \sqrt{196} = \sqrt{14^2} = 14 [/tex]
