According to the molar ratio in the equation, for every 1 mole of HCl, 1 mole of NaCl is formed.
Thus, if 1.9 mol of HCl is used up in the reaction, 1.9 mol of NaCl is formed.
So the answer is 1.9 mol of NaCl.
Considering the definition of limiting reagent and reaction stoichiometry, the total number of moles of NaOH produced is 1.9 moles.
The balanced reaction is:
HCl + NaOH → NaCl + H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Then, the amount of product obtained from the reaction will always depend on the amount of limiting reagent in the reaction.
So you can apply the following rule of three, being HCl the limiting reactant: if by stoichiometry 1 moles of HCl produce 1 moles of NaOH, 1.9 moles of HCl will produce how many moles of NaOH?
[tex]amount of moles of NaOH=\frac{1.9 moles of HClx1 mole of NaOH}{1 mole of HCl}[/tex]
amount of moles of NaOH= 1.9 moles
Finally, the total number of moles of NaOH produced is 1.9 moles.
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