Answer:
5.00 × 10⁻⁴ mol HCl; 100 mL NaOH
Step-by-step explanation:
3. Moles of HCl
Data:
V(HCl) = 500 mL
pH = 3
Calculations:
pH = 3
[H₃O⁺] = 10⁻³ mol·L⁻¹
V = 500 mL × (1 L/1000 mL) = 0.500 L
Moles HCl = volume × concentration
= 0.500 L × (10⁻³ mol/1 L)
= 5.00 × 10⁻⁴ mol
4. Volume of NaOH
NaOH + HCl ⟶ NaCl + H₂O
Data:
[NaOH] = 0.01 mol·L⁻¹
[HCl] = 0.02 mol·L⁻¹
V(HCl) = 50 mL
Calculations:
Moles HCl = 0.050 L × (0.02 mol/1 L)
= 1.0 × 10⁻³ mol
Moles NaOH = 1.0 × 10⁻³ mol HCl × (1 mol NaOH/1 mol HCl)
= 1.0 × 10⁻³ mol NaOH
V(NaOH) = 1.0 × 10⁻³ mol NaOH × (1 L NaOH/0.01 mol NaOH)
= 0.1 L NaOH Convert to millilitres
= 100 mL NaOH
