Answer:
Probability of choosing a heart and rolling a 2 = [tex]\frac{1}{24}[/tex]
Step-by-step explanation:
Let A be the event of choosing a heart from a standard deck of cards and
B be the event of rolling a 2.
Clearly, A and B are independent events as none of the events does not affect the probability of occurrence of other event.
Therefore, P(A∩B) = P(A) × P(B)
P(A) = [tex]\frac{Number of heart cards}{Total number of cards}[/tex]
[tex]=\frac{13}{52}[/tex]
[tex]=\frac{1}{4}[/tex]
P(B) = [tex]\frac{1}{6}[/tex]
P(A∩B) = P(A) × P(B)
= [tex]\frac{1}{4} (\frac{1}{6} )[/tex]
[tex]=\frac{1}{24}[/tex]