Question

in a given binominal distribution, there are 625 trials, and the probability of success is p=0.29. What is the variance?

Answer 1

Answer:

The variance is 129

Step-by-step explanation:

The variance of a binomial distribution is defined as

$np(1-p)$

where n is the number of trials, and p is the prob of success. So in your case the variance is:

$625\cdot 0.29\cdot 0.71 \approx 129$

(I am intentionally rounding to nearest integer to make the variance a meaningful value, since the events are discrete and not fractional measurements)