Question

Mr. Mathewson increased the amount of weight he lifted each morning from 80 pounds to 90 pounds. By what percentage did Mr. Mathewson increase the amount of weight he lifted?

Answer 1

Answer:

Mr. Mathewson increased the amount of weight he lifted by 12.5%

Step-by-step explanation:

90 = 80 + x% × 80

When you increase an amount A by x%, that means you find x% of A, and add it to A. By the way, the percentage decrease to get back to A is _always_ different.

90 - 80 = (80 + x% × 80) - 80

10 = x% × 80

x% = 10÷80

% means divide by 100 (per means divide, cent means 100)

(x÷100) × 100 = (10÷80) × 100

x = 1000 ÷ 80

= 100 ÷ 8

= 25 ÷ 2 = 12.5

x% = 12.5%

Check: 12.5% of 80 is 0.125 × 80 = 10

You might recognize 0.125 as 1/8.

To increase 80 by 12.5% you add

12.5% of 80 to 80, giving 90. ✔

Answer 2

Mr. Mathewson increased the amount of weight he lifted by 12.5 percent.

What is the percentage?

The quantity of anything is stated as though it were a fraction of a hundred. A fraction of 100 can be used to express the ratio.

Mr. Mathewson raised the amount of weight he lifted from 80 to 90 pounds each morning.

Final value = 90 pounds

Initial value= 80 pound

The percentage increment in weight is found as;

$\% \ W=\frac{90-80}{80} \\\\ \% \ W=12.5 \%$

Hence, Mr. Mathewson increased the amount of weight he lifted by 12.5 percent.

To learn more about percentages, refer to:

https://brainly.com/question/13450942

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