Respuesta :
Answer : The molecular of the compound is, [tex]C_6H_8O_2[/tex]
Solution : Given,
Molecular weight of compound = 112.124 amu
The Empirical formula = [tex]C_3H_4O_1[/tex]
First we have to calculate the empirical formula weight.
The empirical formula weight = 12(3) + 4(1) + 1(16) = 56 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
[tex]n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}\\\\n=\frac{112.124}{56}=2[/tex]
Molecular formula = [tex](C_3H_4O_1)_n=(C_3H_4O_1)_2=C_6H_8O_2[/tex]
Therefore, the molecular of the compound is, [tex]C_6H_8O_2[/tex]
(C₃H₄O)₂ is the molecular formula of the compound whose molecular weight is 112.124 atomic mass units.
How we calculate the molecular formula of any compound?
Molecular formula of any compound will be calculated by using the below equation as:
Molecular formula (n) = molecular weight / empirical formula weight
Given compound = C₃H₄O
Empirical formula weight of C₃H₄O = 12(3) + 4(1) + 1(16) = 56 gram/eq
Molecular weight of C₃H₄O = 112.124 amu
Molecular formula (n) for C₃H₄O will be calculated as (C₃H₄O)ₙ
n = 112.124 / 56 = 2
Hence, molecular formula of given compound is (C₃H₄O)₂.
To know more about molecular formula, visit the below link:
https://brainly.com/question/1603500
