Question

Addison is a painter, and she is called for two different jobs.


Mrs. Jolly has a fence that is 38ft long and 4ft high. Mr. Lopez has a fence that is 27ft long and 3ft high. Mr.s Jolly wants one side of her fence painted. Mr. Lopez wants both sides of his fence painted.


Part a) Which job would Addison paint the most fence area for?


Part b) Mrs. Jolly pays $1 for every 4 square feet. Mr. Lopez pays $1 for every 3 square feet. Miss Addison wants the job that pays her the most money.


(This isn't my question, I am trying to explain how to solve it to a 4th grader, who barely knows anything. So, try to put it in the simplest of explanations. Because she just wants me to give the answer. I tried so hard to lead her to the answer.... that I lost my mind and had to post it her to find someone to explain it cause she doesn't understand my hints and explanation...)

Answer 1

Answer:

A. Mrs. Jolly's

B. Mrs. Jolly

Step-by-step explanation:

We have that,

Length and Height of Mrs. Jolly's fence are 38 ft and 4 ft respectively.

Length and Height of Mr. Lopez's fence are 27 ft and 3 ft respectively.

Part A:

Since, the fence resembles a rectangle. We have that the area of rectangle is given by,

Area = Length × Height

So, the area of Mrs. Jolly's and Mr. Lopez's fences are,

Area of Mrs. Jolly's fence = 38 × 4 = 152 ft²

Area of Mr. Lopez's fence = 27 × 3 = 81 ft²

Since, 152 > 81.

So, the most area of the fence is for Mrs. Jolly's fence.

Hence, Addison would paint most fence area of Mrs. Jolly's fence.

Part B: We have,

For every 4 square feet, Mrs. Jolly pays $1.

Then, for 152 square feet, she would pay $\frac{1}{4}\times 152$ = $38.

Similarly, For every 3 square feet, Mr. Lopez pays $1.

Then, for 81 square feet, he would pay $\frac{1}{3}\times 81$ = $27.

Thus, Addison will take the job of Mrs. Jolly.