Answer:
P(55 good before first defective) = 80.66%, so take choice C, 81%.
Step-by-step explanation:
We want probability of 55 or more successes before a failure.
P(success) = 1 - P(failure)
= 1.0000 - 0.0039 = 0.9961
We assume the outcomes are independent.
P(55 successes with no failure) = 0.9961^55 = 0.80660647769
Answer:
P(success) = 1 - P(failure)
? = 1.0000 - 0.0039 = 0.9961
P(55 successes with no failure) = 0.9961^55 = 0.80660647769
the answer is C 81% (we rounded)
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