Answer:
Step-by-step explanation:
1. [tex]4(2x^{2}+3y^{2})^{2}[/tex]
=[tex]4(4x^{4}+9y^{4}+12x^{2}y^{2})[/tex]
= [tex]16x^{4}+36y^{4}+48x^{2}y^{2}[/tex]
2. [tex]4(2x^{2}+3y^{2})(2x^{2}-3y^{2})[/tex]
=[tex]4((2x^{2})^{2}-(3y^{2})^{2})[/tex]
=[tex]4(4x^{4}-9y^{4})[/tex]
= [tex]16x^{4}-36y^{4}[/tex]
3. [tex](4x-5)(16x^{2}+20x+25)[/tex]
=[tex]64x^{3}-80x^{2}+80x^{2}-100x+100x-125[/tex]
= [tex]64x^{3}-125[/tex]
