Question

find the vertical asymptote for y=x^2-5x/x^2-x-2

Answer 1

Answer:

vertical asymptote at x=2  and x=-1

Step-by-step explanation:

$y= \frac{x^2-5x}{x^2-x-2}$

To find out vertical asymptote we set the denominator =0  and solve for x

$x^2 - x - 2=0$

now factor left hand side

find out two factors whose product is -2 and sum is -1

-2 times 1 = -2

-2+1 = -1

(x-2)(x+1) =0

x-2 =0  so x= 2

x+1 =0 so x=-1

vertical asymptote at x=2  and x=-1