Question

Please help
subtract:
2x^2−3xy+4y^2 from 3x^2−5xy−6y^2
x^2+4xy−3y^2 from 2x^2−5xy+y^2
4x^3−6x^2+8x−9 from 7x^3−16x+18

Answer 1

Answer:

x^2 -2xy -10y^2

x^2 -9xy +4 y^2

3x^3  +6x^2  -24 x +27

Step-by-step explanation:

3x^2-5xy -6y^2 -( 2x^2 -3xy+4y^2)

= 3x^2- 2x^2 -5xy +3xy-6y^2 -4 Y^2

= x^2 -2xy -10y^2

2x^2−5xy+y^2 -( x^2+4xy−3y^2)

=2 x^2 -x^2 -5xy -4xy +y^2 +3 y^2

=x^2 -9xy +4 y^2

7x^3−16x+18- (4x^3−6x^2+8x−9)

= 7x^3 -4x^3 + 6x^2-16x- 8x +18 +9

=3x^3  +6x^2  -24 x +27